thanhtruong272
[115712]
07/12/2020 9:47:34 PM
Mong các tiền bối chỉ bảo
$\int {\frac{{2x + 1}}{{(x + 2)({x^2} + 4)}}dx} = \int {\left( { - \frac{3}{{8(x + 2)}} + \frac{3}{{16}}.\frac{{2x}}{{{x^2} + 4}} + \frac{5}{4}.\frac{1}{{{x^2} + 4}}} \right)dx} = - \frac{3}{8}\ln \left| {x + 2} \right| + \frac{3}{{16}}\ln \left| {{x^2} + 4} \right| + \frac{5}{8}\arctan \frac{x}{2} + C.$