Nguyenquang2k4_4
[133697]
26/06/2021 7:21:52 PM
Giúp mk vs. Hướng dẫn cx đc ạ
\[\begin{gathered} y = {x^3} - 3m{x^2} + 4{m^3} \hfill \\ \Rightarrow y' = 3{x^2} - 6mx = 0 \Leftrightarrow x = 0;x = 2m,\left( {2m \ne 0} \right) \hfill \\ \Rightarrow A\left( {0;4{m^3}} \right) \in Oy,B\left( {2m;0} \right) \in Ox \hfill \\ \Rightarrow {S_{OAB}} = \frac{1}{2}OA.OB = \frac{1}{2}\left| {4{m^3}} \right|.\left| {2m} \right| = 4{m^4} = 4 \Leftrightarrow m = \pm 1 \hfill \\ \end{gathered} \]